If two circle have their radii in the ratio of 3:2,then their areas are in the ratio of
Answers
Answered by
40
Hey there!
Given, Ratio of radii of two different circles = 3 : 2
Let the radii be 3r , 2r .
Area of circle = πr²
Area of First circle = π(3r)² = 9πr²
Area of second circle = π(2r)² = 4πr²
Ratio of Areas = 9πr² : 4πr² = 9 : 4
Hope helped!
Given, Ratio of radii of two different circles = 3 : 2
Let the radii be 3r , 2r .
Area of circle = πr²
Area of First circle = π(3r)² = 9πr²
Area of second circle = π(2r)² = 4πr²
Ratio of Areas = 9πr² : 4πr² = 9 : 4
Hope helped!
Swarup1998:
Nice explanation, bro! (-:
Answered by
8
hye
=======================================
two circle have their radii in the ratio of 3:2
=> so let it be 3r and 2r
=>now we have to find their areas are in the ratio of what?
=>area of a circle = π *r² [ r = radius ]
so area of bigger circle = π *r²
radius = 3r
=> π *(3)r²
=> 9r² π
=>area of smaller circle = π *r²
radius = 2r
=> π *(2r)²
=> 4r² π
therir ratios = 9 :4
but this can be simplied further
=> 3:2
=======================================
hope it helps u/..................
=======================================
two circle have their radii in the ratio of 3:2
=> so let it be 3r and 2r
=>now we have to find their areas are in the ratio of what?
=>area of a circle = π *r² [ r = radius ]
so area of bigger circle = π *r²
radius = 3r
=> π *(3)r²
=> 9r² π
=>area of smaller circle = π *r²
radius = 2r
=> π *(2r)²
=> 4r² π
therir ratios = 9 :4
but this can be simplied further
=> 3:2
=======================================
hope it helps u/..................
Similar questions