if two circles intersect at two point prove that their centres lie on the perpendicular bisector on the common chord
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Figure shows two circles intersect at A and B, AB is common chord. P and Q are centres of circles.
Let C is mid point of AB. let us join PC and QC.
In a circle, line drawn from centre of circle to the mid point of chord is perpendicular to that chord.
hence PC is perpendicular to AB and QC is perpendicular to AB.
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