Question

if two circles intersect at two points prove that their centres lie in the perpendicular bisector of the common chord

explain properly with figure​

Answer 1

Answer:

refer to the attachment

Step-by-step explanation:

Let C is mid point of AB. let us join PC and QC

in a circle, line drawn from circle to the midpoint of chord is perpendicular to AB

since, angle PCA and angle ACQ are right angles and C is midpoint of AB, PQ is perpendicular bisector of AB .

Hence, the centres of circle P and Q lie on the perpendicular bisector of common chord AB of two intersecting circles at A and B.

Hope it helped you...