if two circles intersect in C and D point.Two line through the point D and C intersect the circle in A and B point and another circle in E and F point .If angle DAB=75 DEGREE then find angle DEF
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D
(i) 68
o
, (ii) 96
o
∠DEF=110
o
∠ACB=32
o
∠DAB=118
o
ABCD and CDEF are cyclic quadrilateral
∠BAD+∠BCD=180
o
118+∠BCD=180
∠BCD=62
∠BCA+∠ACD=62
32+∠62
∠ACD=30
In ABCD cyclic quadrilateral
∠BCA=∠BDA
∠BDA=32
o
(angle in major sector from same chord)
∠BDA=∠EDF=32
o
(opposite angle)
In △DEF
∠DEF+∠EDF+∠DFE=180
∠DFE=180−32−110=38
o
∠DFE=∠DCE=38
o
(angle in major segment from same chord)
i)∠ACE=∠ACD+∠DCE=30+38=68
o
ii)∠COD=96
o
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