if two circles touch each other externally prove that center and point of contact and collinear
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Two circles with centres A and B touch each other at P externally.
To prove: A,B and P are collinear.
Construction: Draw the common tangent at P. Join AP and BP.
Proof: ∠APQ=90
o
.....(i)
(Radius is perpendicular to the tangent)
∠BPQ=90
o
.....(ii)
(radius is perpendicular to the tangent)
Adding (i) and (ii), we get
∠APQ+∠BPQ=90
o
+90
o
⇒∠APB=180
o
⇒ APB is a straight line
∴ A,B and P are collinear.
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