Question

if two circles touch each other externally prove that the centre and the point of the contract are colinear ​

Answer 1

hello. .......

By adding the points P,O,S and also the points Q,O; ans R,O.

From the given condition , ∠POQ=90°

=∠ROS. [since, the angle as described like semi-circle is a right angle.]

Now,from the figure we see ∠POR=180°−90°=∠QOS. And hence,∠POQ+∠QOS=90°+90°=180°=∠POS.

Hence ,we can conclude P,O,S are collinear.

However, that the distance between the two centres will be equal to the difference between the two radii is because the centres and the contact point are colinear...

hope it help u

Answer 2

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mananmadani53

nrkubakaddi1953

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if two circles touch each other externally prove that the centre and the point of the contract are colinear ​

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hello. .......

By adding the points P,O,S and also the points Q,O; ans R,O.

From the given condition , ∠POQ=90°

=∠ROS. [since, the angle as described like semi-circle is a right angle.]

Now,from the figure we see ∠POR=180°−90°=∠QOS. And hence,∠POQ+∠QOS=90°+90°=180°=∠POS.

Hence ,we can conclude P,O,S are collinear.

However, that the distance between the two centres will be equal to the difference between the two radii is because the centres and the contact point are colinear...

Step-by-step explanation:

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