If two circles (x - 1)2 + (y - 3)2 = r2 and x2 + y2 - 8x +2y +8 = 0 intersect in two distinct
points, then
(A) 2 <r<8
(B) r <2
(C) r = 2
(D)r > 2
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Answer:
b is the correct answer
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