Question

If two circles x^2+y^2+2gx+c=0 and x^2+y^2-2fy-c=0 have equal radius then locus of (g,f) is
1) x^2+y^2=c^2
2)x^2-y^2=0
3)x-y^2=c^2
4)x^2+y^2=2c^2

Answer 1

Answer:

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Answer 2

If two circles x^2+y^2+2gx+c=0 and x^2+y^2-2fy-c=0 have equal radius then locus of (g,f) is

x^2 - y^2 = 0

option 2