Question

If two coins are tossed, find the probability of the following events.
(1) Getting at least one head.
(2) Getting no head.

Answer 1

hey user here is your answer..
2 coins .
head head
head tail
tail head
tail tail.

i) 3/4
ii) 1-3/4
=1/4

hope it helps !!..
:)

Answer 2

Answer:

probability of getting at least one head = $\dfrac{3}{4}$

probability of gettin no head =$\dfrac{1}{4}$

Step-by-step explanation:

According to given condition we are tossing two coins.

If we toss two coins together the possibility of outcomes will be

(Head, head), (head, tail), (tail, head) , (tail, tail)

So, there can be 4 outcomes of tossing two coins together.

(1) probability of getting at least one head = $\dfrac{number\ of\ outcomes\ having\ at\ least\ one\ haed}{total\ number\ of\ head}$

                                                                $=\dfrac{3}{4}$

(2) probability of getting no head =$\ \dfrac{number\ of\ outtcomes\ having\ no\ head}{total\ number\ of\ outcome}$

                                                        $=\ \dfrac{1}{4}$

Hence, the probability of getting at one head is $\dfrac{3}{4}$ and probability of getting no head is $\dfrac{1}{4}$