if two coins are tossed , find the probability of the event "getting at most one head."
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Answered by
2
Answer:
3/4
Step-by-step explanation:
sample space= {HH , HT ,TT ,TH} n(S) = 4
getting atleast one head = {HH,HT,TT} n(A) = 3
probability =n(A)/n(S) =3/4
Answered by
0
Answer:
3/4
Step-by-step explanation:
sample space= {HH , HT ,TT ,TH} n(S) = 4
getting atleast one head = {HH,HT,TT} n(A) = 3
probability =n(A)/n(S) =3/4
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