If two coins are tossed,find the probability of the folloing events.
1)Getting atleast one head.
2)Getting no head.
Use formula n(A) upon n(S).
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Answered by
2
probability = A/N
therefore, the outcomes are h,t ; t,h ; h,h
hence probability will be 1/4,1/4,2/4
outcomes t,t
probability 2/4
therefore, the outcomes are h,t ; t,h ; h,h
hence probability will be 1/4,1/4,2/4
outcomes t,t
probability 2/4
Answered by
1
HERE IS THE ANSWER OF YOUR QUESTION :-
__________________________
# Outcomes that came after tossing the coin are are :-
HH, TH, HT, TT.
1) Total number of outcomes = 4.
Number of favourable outcomes = 3
P ( getting at least one head ) = Favourable outcomes / Toatal number of outcomes. [ A / S ]
= 3/ 4
2. Total number of outcomes = 4
Number of favourable outcomes = 1
P ( getting no head ) = A / S
= 1/ 4
______________________________________________
HOPE IT HELPS YOU.
__________________________
# Outcomes that came after tossing the coin are are :-
HH, TH, HT, TT.
1) Total number of outcomes = 4.
Number of favourable outcomes = 3
P ( getting at least one head ) = Favourable outcomes / Toatal number of outcomes. [ A / S ]
= 3/ 4
2. Total number of outcomes = 4
Number of favourable outcomes = 1
P ( getting no head ) = A / S
= 1/ 4
______________________________________________
HOPE IT HELPS YOU.
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