if two coins are tossed simultaneous find the probability of getting 1) atleast one tail (2)head on both the coins
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Answer:
S={TT,HH,HT,TH}
Let A be the event when it is Atleast one tail
A={TT,TH,HT}
n(A)=3
p(A)=n(A)/n(s)
=3/4
Let B be the event of head on both the coins
B={HH}
n(B)=1
p(B)=1/3
Answered by
3
1. 3/4
2.1/4
Hope you understand
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