If two coins are tossed simultaneously 500 times. If we get two heads 100 times, one head 270 times and no head 130 times, then find the probability of getting one or more than one head. *
1 point
35/50
27/50
37/50
1/5
Answers
Answered by
0
Answer:
hey mate here is your answer ☺️☺️
Step-by-step explanation:
Given
Totalnumberoftimes2coinsaretossed=500
Nooftimes2Headscomesup=95
Nooftimes1Tailcomesup=290
NooftimesNoHeadcomesup=115
Probabilityof2Headscomingup=
Totalnumberoftimes2coinsaretossed
Frequencyof2Headscomingup
=
500
95
=0.19
Probabilityof1Tailcomingup=
Totalnumberoftimes2coinsaretossed
Frequencyof1Tailcomingup
=
500
290
=0.58
ProbabilityofNoHeadscomingup=
Totalnumberoftimes2coinsaretossed
FrequencyofNoHeadscomingup
=
500
115
=0.23
Answered by
2
Answer:
hi..............................................................
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