Question

If two coins are tossed simultaneously. Find the probability of the following events. *​

Answer 1

Answer:

When two coins are tossed, sample space S is given by {HH,HT,TH,TT} and therefore, n(S)=4.

Let A denote the event that both head appear that is {HH} and n(A)=1, therefore, probability of both head appear is:

P(A)=

n(S)

n(A)

=

4

1

Let B denote the event that both tail appear that is {TT} and n(B)=1, therefore, probability of both tail appear is:

P(B)=

n(S)

n(B)

=

4

1

Intersection of A and B is the common elements between A and B which is none, thus, n(A∩B)=0 and

P(A∩B)=

n(S)

n(A∩B)

=

4

0

=0

Therefore, the events are mutually exclusive.

The probability of either both head or both tail occur is P(A∪B) and we know that for mutually exclusive event, P(A∪B)=P(A)+P(B) that is:

P(A∪B)=P(A)+P(B)=

4

1

+

4

1

=

4

2

=

2

1

Hence, probability that either both heads or both tails occur is

2

1

.

Step-by-step explanation:

hope it's helpful to you.

Answer 2

Answer:

What events are you talking about.

(a)(h,h)

(b)(t,t)

(c)(h,t)

(d)(t,h)

The above are the outcomes.

HOPE IT HELPS!!!!!!!!