If two coins are tossed simultaneously find the probablity of getting out at least on head.
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when two coins are posted the result comes out are-
both the heads-HH
one head and one tail-HT
one tail and one head-TH
both the tail- TT
let A be the event of costing and getting at least one head the chances of getting at least one head 1,2,3 from the above chances qualifying for the criteria to the probability
P(A)=number of outcome favourable to A/the number of the all possibilities coming out through the experiment.
P(A)= there are three possibilities/and two coins are tossed it so to head and to tell that means four
=3/4
so the answer is 3 / 4
both the heads-HH
one head and one tail-HT
one tail and one head-TH
both the tail- TT
let A be the event of costing and getting at least one head the chances of getting at least one head 1,2,3 from the above chances qualifying for the criteria to the probability
P(A)=number of outcome favourable to A/the number of the all possibilities coming out through the experiment.
P(A)= there are three possibilities/and two coins are tossed it so to head and to tell that means four
=3/4
so the answer is 3 / 4
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3/4 or 0.75 is the probability of getting out at least one head
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