If two coins are tossed then find the probability of getting no tail
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total outcome=4 (hh,ht,th,tt)
fav outcome= 1
probability =fav. outcome/total
=1/4
fav outcome= 1
probability =fav. outcome/total
=1/4
walker77:
r u there
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When two different coins are tossed randomly, the sample space is given by
S = {HH, HT, TH, TT}
Therefore, n(S) = 4.
Let E= event of getting no tail. Then,
E= {HH} and, therefore, n(E) = 1.
Therefore, P(getting no tail) = P(E) = n(E)/n(S) = ¼.
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