Question

If two complementary angles are in the ratio 7:11, the supplement of the larger angle is _________.​

Answer 1

Answer:

Answer. Let x be common multiple in ratio of angles. Sum of supplementary angles = 180°. Now angles are 7x = 70°.

Step-by-step explanation:

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Answer 2

Answer:

The supplement of the larger angle is 135°.

Step-by-step explanation:

Given ratio of two complementary angles is 7:11.

Let first complementary angle be$7x$

and second complementary angle be $11x.$

We know,sum of two complementary angles$= {90}^{o}$

So,

$7x + 11x = {90}^{o}$

$18x = {90}^{o}$

$x = \frac{ {90}^{o} }{18}$

$x = {5}^{o}$

Therefore first angle is ${(7 \times 5)}^{o} = {35}^{o}$

and second angle is ${(9 \times 5)}^{o} = {45}^{o}$

Here largest angle is 45°.

Supplementary angle of 45° is $( {180}^{o} - {45}^{o} ) = {135}^{o}$