Question

If two consecutive sides of a rhombus are represented by 3x-6 and x+14 , then the perimeter of rhombus is

Answer 1

Two adjacent sides are given by 3x-6 and x+14.
Now, because its a rhombus all sides of it are equal.
By the problem,
3x-6=x+14
2x=20
x=10
Perimeter of rhombus- 4a (a=side of rhombus)
4*10=40 units

Answer 2

The perimeter of the rhombus is 96 unit

Given :

Two consecutive sides of a rhombus are represented by 3x - 6 and x + 14

To find :

The perimeter of the rhombus

Solution :

Step 1 of 3 :

Find the value of x

Here it is given that two consecutive sides of a rhombus are represented by 3x - 6 and x + 14

Since all sides of a rhombus are equal in length

Thus we get

3x - 6 = x + 14

⇒ 3x - x = 6 + 14

⇒ 2x = 20

⇒ x = 10

The value of x = 10

Step 2 of 3 :

Find side of rhombus

Length of each side

= 3x - 6 unit

= ( 3 × 10 ) - 6 unit

= 30 - 6 unit

= 24 unit

Step 3 of 3 :

Find perimeter of the rhombus

Hence perimeter of the rhombus

= 4 × Length of each side

= 4 × 24 unit

= 96 unit

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