Question

if two consecutive sides of a rhombus are represented by the 3x-6 and x+14,then the perimeter of the rhombus is

Answer 1

Answer:

96

Step-by-step explanation:

we know that in a rhombus all the sides are equal so,

x+14 = 3x - 6

=> 2x = 20

=>  x = 10

so putting x in (x+14)

we get the side is equal to 24

perimeter = 4*(side)

                 = 4*24

                 =96

Answer 2

Answer:

Two adjacent sides are given by 3x-6 and x+14.

Now, because its a rhombus all sides of it are equal.

By the problem,

3x-6=x+14

2x=20

x=10

Perimeter of rhombus- 4a (a=side of rhombus)

4*10=40 units

Step-by-step explanation: