Question

if two consecutive sude of a rhombus are presented by 3x-6 and x+14 then find the perimeter of rhombus​

Answer 1

Answer:

The Answer is 10

Step-by-step explanation:

3x-6 = x+14

2x = 20

x = 10

Answer 2

Answer:

Given :-

Two consecutive sides of a rhombus are represented by 3x-6 and x+14

To find :-

Find the perimeter of the rhombus ?

Solution :-

Given that :

The consecutive sides of a rhombus are 3x-6 and x+14

In a rhombus all sides are equal

so given two sides are equal

3x-6 = x+14

=> 3x-x = 14+6

=> 2x = 20

=> x = 20/2

=> x = 10

the side = 3x-6 = 3(10)-6 = 30-6 = 24

So all sides are equal to 24 units each

So the value of side = 24units

perimeter of a rhombus = 4×side

=> P = 4×24

=> P = 96 units

Answer:-

The perimeter of the given rhombus is 96 units.