If two curves y=x^2-1,y=ax^2-4x+1 at (1,0) touch each other then a=
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Answer:
a = 3.
Step-by-step explanation:
x =1 ; y = 0.
x^2 = 1 ; ( 1st eqn.)
x = 1.
a - 4 + 1 = 0; ( 2nd eqn.)
a = 3.
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