Question

if two diagonal of a rhombus are of length 240 M and 44 M then find the height and perimeter of a rhombus​

Answer 1

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$\huge\mathfrak\blue{Question:}$

If two diagonal of a rhombus are of length 240 m and 44 m then find the height and perimeter of the rhombus​.

$\huge\mathfrak\red{Solution:}$

Area = base × height

a = b × h

$h\:=\:a/b$

-.-.-.-.-.-.-.-.-.-.-.-

Here, diagonals d1 = 240 m and d2 = 44 m

Therefore, area, a = 240 × 44 / 2

a = 120 × 44

a = 5280 m^2

-.-.-.-.-.-.-.-.-.-.-.-

AC = 240 m

Therefore, OC = 120

and BD = 44 m

Therefore, OB = 22

-.-.-.-.-.-.-.-.-.-.-.-

Perimeter, p = 4 × side

side^2 or s^2 = (120)^2 + (22)^2

s^2 = 14400 + 484

s^2 = 14884

s = 122

Now perimeter p = 4 × side

p = 4 × 122

p = 488 m

-.-.-.-.-.-.-.-.-.-.-.-

Height h = area / base

h = 5280/122

h = 43.27 m

Hence, perimeter = 488 m and height = 43.27 m.

(Figure is in the attachment. Kindly refer it for better understanding.) ✌✌

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