if two diagonals of a rhombous are of length 90m and 400m then find the height and perimeter of the rhombous
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Question:
if two diagonals of a rhombous are of length 90m and 400m then find the height and perimeter of the rhombous
Answer:
820m
Step-by-step explanation:
Let the Rhombus be ABCD
We know that :
Diagonal = A.C. = 90cm
Diagonal = BD = 400 cm
Triangle DOC is an right angles triangle
(DC)^2 = (OD)^2 + (OD)^2 [pythagorus]
(DC)^2 = (200)^2 + (45)^2
(DC)^2 = (40,000) + (2,025)
(DC)^2 = 42,025
(DC) = root (42,025)
(DC) = 205cm
Perimeter = 205 × 4
Perimeter = 820m
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- Diagonals of rhombus = 90m and 400m
- Height
- perimeter
Formula for finding the side of rhombus when diagonals are given.
Area of rhombus when diagonals are given:-
Area of rhombus = 18000
- base = 205 m
Perimeter of rhombus :-
So,
★ Height of rhombus = 87.8m
✦ Perimeter of rhombus = 820m
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