Question

If two diagonals of a Rhombus are 6 cm and 8 cm, then Perimeter of the Rhombus is :​

Answer 1

GIVEN=ABCD IS A RHOMBUS IN WHICH AC=8cm AND BD=6cm. THESE DIAGONALS ARE INTERSECTING AT A POINT O ,SUCH THAT LAOB=90°.

TO FIND:PERIMETER OF THE RHOMBUS.

SOLUTION: SINCE AC=8cm,OA=4cm

And,BD=6cm,OB=3cm.

BY PYTHAGORAS PROPERTY, WE HAVE

AB^=OB^+OA^

or, AB^=(3^+4^) cm

or,AB^=(9+16 )cm

or,AB=root 25

orAB=5cm

SINCE,ALL THE SIDES OF THE RHOMBUS ARE EQUAL=(5+5+5+5)cm=20cm

HENCE,THE PERIMETER OF THE RHOMBUS=20cm.

Hope it helps you.