If two diameters of a circle intersect each other at right angles, then quadrilateral formed by joining their end points is -
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square
Step-by-step explanation:
Let AB and CD be the diagonals of a circle such that AB⊥CD
Joining points A,b,C,D in order we see that AB and CD are the equal diagonals of quad. ACBD which intersect at rightangle.
∴ ACBD is a square.
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