Question

If two dice are rolled simultaneously find the probability when sum of the digits on the upper face is divisible by 3.​

Answer 1

I cant answer this question.

Answer 2

S= {(1,1) (1,2), (1,3), (1,4), (1,5), (1,6),

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

n(S)= 36

Let A be the event that the sum of the digits on the upper face is divisible by 3.

A= {(1,2), (1,5), (2,1), (2,4), (3,3), (3,6), (4,2), (4,5), (5,1), (5,4), (6,3),

(6,6)}

n(A)= 12

P(A) = n(A) / n(S)

= 12/ 36

= 1/3

The probability of getting the sum of the digits on upper face

which is divisible by 3 is 1/3.

I hope this solution will help you out!!!