Question

If two dice are thrown in air, the probability of getting sum as 3 will be

Answer 1

To find:

Probability of getting sum as 3 when two dice are thrown in air.

Calculation:

The total possible outcomes are :

$\rm{sample \: space = {6}^{2} = 36}$

The whole sample space is:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

The number of favourable outcomes :

$\rm{favourable \: outcomes = 2}$

The favourable outcomes are :

(1,2) and (2,1)

So , probability P:

$\rm{P = \dfrac{favourable \: outcome}{sample \: space} }$

$= > \rm{P = \dfrac{2}{36} }$

$= > \rm{P = \dfrac{1}{18} }$

So, final answer is:

$\boxed{ \bf{P = \dfrac{1}{18} }}$