if two dice are thrown once find the probability of getting 9
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Answer:
1/9
Step-by-step explanation:
Probability of getting 9
= (3+6) (4+5) (5+4) (6+3)
= ((1/6)*(1/6))*2+((1/6)*(1/6))*2
=(1/36)*2+(1/36)*2
=(1/18)+(1/18)
=2/18
=1/9
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