Question

If two dice are thrown simultaneously, then find the probability that the sum of numbers appeared on the dice is 6 or 7?​

Answer 1

Answer:

11/36

Step-by-step explanation:

let a be the event of getting the sum as 6

a={(1,5),(2,4),(3,3),(4,2),(5,1)}

let b be the event of getting the sum as 7

b={(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)}

n(s) =36

n(a) =5 p(a) =5/36

n(b) =6 p(b) =6/36

p(a) +p(b) =11/36

Answer 2

Step-by-step explanation:

When two dices are rolled , there are

6

×

6

=

36

outcomes of the type

(x,y),where x is outcome of first dice and y is outcome of second dice. As both x and y can take values from 1 to 6,there are total 36 outcomes.Of these the outcomes (1,5), (2,4) ,

(3,3),(4,2) and (5,1) denote we have a got a sum of 6 and the outcomes (1,6) , (2,5) , (3,4) , (4,3) , (5,2) and (6,1)

denote we have a got a sum of

7.

Hence there are

11

outcomes (of the total of

36

outcomes) which give us the desired output.

Hence probability of getting a sum of 6 or 7 is

11

36

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