Question

If two dice are thrown simultaneously, then find the probability that the sum of numbers appeared on the dice is 6 or 7?

Answer 1

Answer:

$\boxed {Probability = \frac{11}{36} }$

Step-by-step explanation:

Given - that two dice are thrown , Then

SAMPLE SPACE

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

$\bigstar$ In This question we are asked to Find the  probability that the sum of numbers appeared on the dice is 6 or 7.

So let us look at the sample space,

$\bigstar$ The Favourable Events are :-  (1,5),(1,6),(2,4),(2,5),(3,3),(3,4),(4,2),(4,3),(5,1),(5,2),(6,1)

$\bigstar$ Number of Favourable Events are :- 11

$\bigstar$ Total Number of outcomes when two dice are thrown = 36

$Probability \: of\: an\: event =\frac{Number \:of\: Favourable\: Outcomes}{Total \:number \:of\: outcomes}$

$Probability\: that \:the\: sum \:of \:numbers\: appeared \:on\: the \:dice \:is \: 6\: or\: 7 = \frac{11}{36}$