Question

If two dice are thrown simultaneously, then the probability of getting a doublet or a total of 6 is

Answer 1

Hey ya!

The total number of outcomes = 36

Favourable outcomes for getting a doublet = 6

{ (1,1) (2,2) (3,3) (4,4) (5,5) (6,6) }

Probability of getting a doublet = 6/36 = 1/6.

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Favorable outcomes for getting a total of 6 =5

{ (1,5) (2,4) (3,3) (4,2) (5,1) }

Probability of getting a total of 6 = 5/36.

:)

Answer 2

Hi friend,

Total outcomes when rolling 2 dice =36

Probability of getting doublet=P(A)= { (1,1) (2,2) (3,3) (4,4) (5,5) (6,6)}=6/36
Probability of getting  sum as 6=P(B)={ (1,5) (2,4) (3,3) (4,2) (5,1)}=5/36
Probability of getting both sum as 6 and also a doublet =P(A∩B)={(3,3)}=1/36
 
So,probability of getting a doublet or a total of 6 is calculated using addition theorem of probability 
P(A∪B)=P(A)+P(B)-P(A∩B)
            =6/36+5/36-1/35=11/36-1/36=10/36=5/18

HOPE THIS HELPS.....