If two dice are thrown simultaneously what is the probability of getting number 2 ?
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Step-by-step explanation:
So, the number of favourable outcomes is 3. We know that the number of possible outcomes is 36. Thus, the probability of getting a doublet of an even number is =336=112.
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Total outcomes when rolling 2 dice = 36
probability of getting doublet = P(A)={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}=6/36
probability of getting sum as 6=P(B)=
{(1,5),(2,4),(3,3),(4,2),(5,1)}=5/36
probability of getting a doublet and
total of 6 is P(A∩B)={(3,3)}=1/36
probability of getting a doublet or a
total of 6=P(A∪B)=P(A)+P(B)−P(A∩B)
=6/36+5/36−1/36
=10/36=5/18
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