If two dice are thrown together find
the probability of the event that the sum of two numbers is more than 2.
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so, there are 6 sides in the dice...
if we take out 1 side from both...it will be 5...
(1+1 = 2) not more than too...so we have to minus that...
so now our equation is=
5+5/12
so,
10/12
then==>
5/6 answer
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