Question

If two dice are thrown together, then what must be the greatest possible score? Write the probability.

Answer 1

Answer:

The required probability is

$\frac{1}{36}$

Step-by-step explanation:

Concept used:

Probability of an event E is

P(E)=(No.of favourable ways to E)/Total no. of ways

$P(E)=\frac{n(E)}{n(S)}$

When two dice are thrown,

S={(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

n(S)=36

From the above,

the greatest possible score is 12

Let E be the event of getting greatest score.

Then,

E={(6,6)}

$P(E)=\frac{n(E)}{n(S)}$

$P(E)=\frac{1}{36}$

Answer 2

Answer:

1/36

Step-by-step explanation:

If two dice are thrown together, then what must be the greatest possible score? Write the probability.

Each dice has score 1 to 6

Greatest possible score = 36

there will only one event when both dice have 6 as score.

Total number of possible of events

= 6 * 6 = 36

Probability of the greatest possible score = 1/36

If we interpret question differently that which score has maximum possibilty

than

Sum 2 comes  1 time

Sum 3 comes  2 time

Sum 4 comes  3 time

Sum 5 comes  4 time

Sum 6 comes  5 time

Sum 7 comes 6 time

Sum 8 comes 5 times

sum 9 comes  4 time

Sum 10 comes 3 time

Sum 11 comes 2 times

sum 12 comes  1 time

Sum 7 comes maximum time and has the greatest possibility

Probability = 6/36 = 1/6