Question

If two dice are thrown together, what is the probability of getting, (a) Sum of 11, (b) Same number on both the dice, (c) Prime numbers on both the dice
class 7 ​

Answer 1

Answer:

5.56% , 1/6 , 5/12

Step-by-step explanation:

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Answer 2

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Probability of an event = Number of outcomes favourable to that event/ Number of all possible outcomes.

The set of all possible outcomes is called the sample space and is denoted by S.

When two dice are tossed, the possible outcomes are (1,1),(1,2),(1,3),(1,4),(1,5),(1,6), (2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).

Hence n(S) = 36.

But we want the desired event E that the number should be same on both dice. Such outcomes (1,1),(2,2),(3,3)(4,4),(5,5) and (6,6). We have 6 desired outcomes. So n(E) = 6

Hence the probability of getting same number. on both dice = n(E)/ n(S) = 6/36 = 1/6

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