Social Sciences, asked by 18441506006, 11 months ago

If two dice are thrown what are the various total number of dots that may turn up?what are the probabilities of each of them?what is the probability that the number of dots will total at least four?

Answers

Answered by Anisha5119
9

Answer:

(1 , 2, 3, 4, 5,6) ( 1) (2) (3)(4) (5)(6)

Answered by ParvezShere
8

When two dice are thrown together , the minimum total number of dots is 2(1,1) and the maximum dots possible are 12(6,6).

Probability of 2 dots(1,1) = 1/36 = 1/36

Probability of 3 dots((2,1)(1,2)) = 2/36 = 1/18

Probability of 4 dots((2,2)(3,1)(1,3)) = 3/36 = 1/12

Probability of 5 dots((4,1)(1,4)(2,3)(3,2)) = 4/36 = 1/9

Probability of 6 dots((3,3)(4,2)(2,4)(5,1)(1,5)) = 5/36 = 5/36

Probability of 7 dots((4,3)(3,4)(5,2)(2,5)(6,1)(1,6)) = 6/36 = 1/6

Probability of 8 dots((6,2)(2,6)(5,3)(3,5)(4,4)) = 5/36 = 5/36

Probability of 9((5,4)(4,5)(6,3)(3,6)) dots = 4/36 = 1/9

Probability of 10 dots((5,5)(6,4)(4,6)) = 3/36 = 1/2

Probability of 11 dots((5,6)(6,5)) = 2/36 = 1/18

Probability of 12 dots(6,6) = 1/36 = 1/36

Probability that the number of dots will total at least 4 = 6/36 = 1/6

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