Question

If two dice are thrown, what is the probability of throwing two sixes, what is the probability of
throwing a total of 9, what is the probability of not throwing a total of 9?​

Answer 1

All the Probabilities of two dice are given in the attachment :)

1) Probability of throwing two sixes

Favourable outcome of getting (6,6) = 1

Total outcomes = 36

P(E) = Favourable outcome/ Total outcome

P(E) = 1/36

2) Probability of throwing a total of 9

3 + 6 = 9 ; (3,6)

4 + 5 = 9 ; (4,5)

5 + 4 = 9 ; (5,4)

6 + 3 = 9 ; (6,3)

Favourable outcome = 4

Total outcomes = 36

P(E) = Favourable outcome/ Total outcome

P(E) = 4/36 or 1/9

3) Probability of not throwing a total of 9

P(E) + P(Ē) = 1

1/9 + P(Ē) = 1

P(Ē) = 1 - 1/9

Taking LCM, we get P(Ē) = 8/9