if two dice are tossed and the list of the 1-5 then probability that the sum tense and more is
Attachments:
Answers
Answered by
1
sample space = { (1,5),(2,5)(3,5)(4,5)(5,5)(6,5)(5,1)(5,2)(5,3)(5,4)}
n (s) = 11
event = {(5,5)(5,6)(6,5)}
n(e)= 3
probability = 3/11
n (s) = 11
event = {(5,5)(5,6)(6,5)}
n(e)= 3
probability = 3/11
Similar questions