Question

if two dice at twice find the prpobilty of top sum appearing odd numbe​

Answer 1

Answer:

A= sum of the numbers appearing on two dice is 6

=(1,5),(5,1),(2,4),(4,2),(3,3)

n(A)=5

B= number 4 has appeared at least once

=(1,4),(4,1),(2,4),(4,2),(3,4),(4,3),(4,4),(4,5),(5,4),(4,6),(6,4)

A∩B=(2,4),(4,2)

n(A∩B)=2

Required probability = P(B/A)=

n(A)

n(A∩B)

​

=

5

2

​

Step-by-step explanation:

Answer 2

Answer:

if you list the possibilities “manually”: [(1,1),(1,3),(3,1),(3,3),(1,5),(5,1),(3,5),(5,3),(5,5)]