Question

If two dice thrown simultaneously, find the probability of getting 4 as the sum of the two numbers appearing on the top

Answer 1

Answer:

n(S) = 36

let A be the event of getting 4 as sum of the digits on upper face.

A = { 1,3 ; 2,2 ; 3,1 }

n(A) = 3

p(A) = n(A) / n(S)

= 3 / 36

= 1 / 12

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Answer 2

The probability of getting 4 as the sum of the two numbers appearing on the top is $\frac{1}{12}$

Solution:

The probability of an event is given as:

$Probability = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}$

Given that,

Two dice thrown simultaneously

Sample space is:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Therefore.

Total number of possible outcomes = 36

Favorable outcomes = getting 4 as the sum of the two numbers appearing on the top

Number of favorable outcomes = (1, 3) , (2, 2) , (3, 1) = 3

Find probability of getting 4 as the sum of the two numbers appearing on the top

$Probability = \frac{3}{36}\\\\Probability = \frac{1}{12}$

Thus probability is found

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