Question

If two dice tossed find the probability of throwing a total of 10or more.

Answer 1

Answer:

Step-by-step explanation:

since the dice is thrown twice,the total possible outcomes are:

{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

total number of outcomes=36

now,

the possibility of getting the sum of two numbers as 10 or more is:

(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)=n(e)

therefore,

p(e)=n(e)/n(s)

p(e)=6/36

p(e)=1/6