Question

If two dies are thrown simultaneously what is the prob. Of one of the dice getting face 6 ?



a. 11/36



b. 1/3



c. 12/35



d. 1/36

Answer 1

Hi there!
Here's the answer:

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Let S be sample space
n(S) - no. of total outcomes when two dice are rolled

n(S) = 6² = 36

E be the Event that one of die shows 6
E = {(1,6) , (2,6) , (3,6) , (4,6) , (5,6) , (6,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) }

n(E) is nothing but no. of these possible cases
n(E) = 11

For an event,
Probability = Possible no. of outcomes/Total no. of Outcomes

probability = n(E) / n(S)
•°• Required probability = 11/36

This answer exists in option (a.)

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:)
Hope it helps