Question

If two dies are thrown , the possible outcomes which can be written as ordered pairs

(1,1), (1,2), (1,3) (6,5),(6,6). Among them , (1,1) is the only pair that shows 2 as

the sum of its numbers and the pair (6,6) shows a sum of 12.

We know that the probability of getting a pair with the sum 2 is 1/36. Now answer the

following:


a) What is the probability of getting the sum 12 ?

b) Which pairs show the sum 5 ?

c) What is the probability of getting the sum 5 ?

d) How many pairs give the sum 10 ?

e) What is the sum with the maximum possibility of occurrence?

f) What is the probability of getting a pair with the sum of 7 ?
please answer now and correct

Answer 1

Answer:

a.1/36

b.1,4. 2,3. 3,2. 4,1

c.1/9

d.5,5. 4,6. 6,4

e.7

f.1/6

Answer 2

Answer:

a) 1/36

b) (1,4) (2,3) (3,2) (4,1)

c) 4/36 or 1/9

d) 3 pairs (4,6) (5,5) (6,4)

e) 12

f) 6/36 or 1/6