Question

if two different bodies of masses m1 and m2 are dropped from the same height what is the ratio of their linear momentum​

Answer 1

Explanation:

From second equation of motion,

s=ut+21at2

Given, u=0, a=g, s1=h1, s2=h2 

h1=(1/2)g(t1)2

h2=(1/2)g(t2)2

So, h1/h2=(t1)2/(t2)2

or(t1)/(t2)=h2h1

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