Question

If two different dice are rolled together, find the probability of getting (1) an even number on first Dice (2) an even number on both sides

Answer 1

in first number of possible otcome/total number of outcome
total number of outcome in 1 is 6
favorable is
so 3/6
in second total number 3 but favorable 6
so6/36

Answer 2

Answer:

1) 1/2

2)1/4

Step-by-step explanation:

Two dice are rolled .

Total out comes :

{1,1} ; {1,2} ; {1,3} ; {1,4} ; {1,5} ; {1,6}

{2,1} ; {2,2} ; {2,3} ; {2,4} ; {2,5} ; {2,6}

{3,1} ; {3,2} ; {3,3} ; {3,4} ; {3,5} ; {3,6}

{4,1} ; {4,2} ; {4,3} ; {4,4} ; {4,5} ; {4,6}

{5,1} ; {5,2} ; {5,3} ; {5,4} ; {5,5} ; {5,6}

{6,1} ; {6,2} ; {6,3} ; {6,4} ; {6,5} ; {6,6}

So, total outcomes = 36

1)  an even number on first Dice

favorable outcomes: {2,1} ; {2,2} ; {2,3} ; {2,4} ; {2,5} ; {2,6} ; {4,1} ; {4,2} ; {4,3} ; {4,4} ; {4,5} ; {4,6} ; {6,1} ; {6,2} ; {6,3} ; {6,4} ; {6,5} ; {6,6} = 18

So probability of getting an even number on first Dice = 18/36 = 1/2

(2) an even number on both sides

Favorable outcomes : {2,2}; {2,4} ; {2,6};  {4,2} ; {4,4} ; {4,6} ; {6,2} ; {6,4} ; {6,6} = 9

So,  probability of getting an even number on both sides= 9/36 = 1/4