Question

If two different dices rolled together calculate probablity of even number on both dice

Answer 1

As even no.are 2,4,6

So 2 dice probeblity is 3*3 =9=9\36

Answer 2

$\underline{\underline{\Huge\mathfrak{ANSWER :}}}$
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$\underline\text{Using the Formula,}$

$\boxed{\mathsf{P(E) = \frac{Number \: of \: Favourable \: Outcomes}{Total \: Number \: of \: Outcomes} }}$

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POSSIBLE OUTCOMES ARE :-

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

= $\bf{36}$

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FAVOURABLE OUTCOMES :-

(2,2) (2,4) (2,6)
(4,2) (4,4) (4,6)
(6,2) (6,4) (6,6)

= $\bf{9}$

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Now,

$\underline\text{Putting the values in the Formula,} \\\underline\text{We get,}$

P(E) = $\large\mathsf{\frac{\cancel{9}}{\cancel{36}}}$

=> P(E) = $\large\mathsf{\frac{1}{4}}$

Hence, the probability to get even numbers on both dice is $\large\mathsf{\frac{1}{4}}$
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$\boxed{\boxed{\boxed{\Large\mathsf{THANKS}}}}$

$\huge\mathbf{\# \: Be Brainly}$