If two digit number digit at the tens tens place is twice the digit at the unit place if number obtained by interchanging the digit is added to the original number the sum is 66
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Let’s assume the digit at the unit’s place to be x.
Digital at tens place = 2x
Original number = 2x × 10 + x = 21x
Now, the number obtained by interchanged the digits = x × 10 + 2x = 12x
From the given information,
12x + 21x = 66
33x = 66
⇒ x = 2
So, the unit’s digit = 2 and the ten’s digit = 2 x 2 = 4
Therefore, the number is 42.
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