if two ends of an ideal rope are pulled with forces of equal magnitude of 100N in opposite directions, the tension at the center of the rope must be
Answers
0 N
The tension T is same on the half string on both sides of the forces.
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Answer: 0 N
Concept: Tension, Newton's Law of Motion
Given: F1 = 100N
F2 = 100N
=> F1 = - F2
To Find: Tension at the center of rope
Explanation:
Force acting downward at the center of rope is,
W = mg ..........(1)
where, g is the gravitational constant.
also, there is a force acting upward, R
R = m(-g) = -mg ..........(2)
(-ve sign due to upward gravitational force)
now from (1) and(2)
W = - R ......... (3)
which cancel the upward and downward forces.
As of Forces from opposite directions (from left and right);
Tension is applied on both the faces, which is equal and opposite in magnitude.
therefore, the net tension is zero.
T = -F ......(4)
as we know,
F1 = - F2
So, -T1 = T2 (From eqn. 4)
Hence, The net tension is 0.
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