Question

if two ends of an ideal rope are pulled with forces of equal magnitude of 100N in opposite directions, the tension at the center of the rope must be

Answer 1

0 N

The tension T is same on the half string on both sides of the forces.

Hope it helps!!

Answer 2

Answer: 0 N

Concept: Tension, Newton's Law of Motion

Given: F1 = 100N

           F2 = 100N

=> F1 = - F2

To Find: Tension at the center of rope

Explanation:

Force acting downward at the center of rope is,

W = mg  ..........(1)

where, g is the gravitational constant.

also, there is a force acting upward,  R

R = m(-g) = -mg ..........(2)

(-ve sign due to upward gravitational force)

now from (1) and(2)

W = - R ......... (3)

which cancel the upward and downward forces.

As of Forces from opposite directions (from left and right);

Tension is applied on both the faces, which is equal and opposite in magnitude.

therefore, the net tension is zero.

T = -F   ......(4)

as we know,

F1 = - F2

So, -T1 = T2   (From eqn. 4)

Hence, The net tension is 0.

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