Question

if two equal chords of a circle intersect , prove that their segments will be equal​

Answer 1

Given :-> AB and CD are chords of a circle with centre O. AB and CD intersect at E and AB = CD.

To prove : AE = ED and EB = CE.

Construction: Draw OM perpendicular to AB and ON perpendicular CD. Join OE.

AM = MB = 1/2AB (Perpendicular bisecting the chord)

CN = ND = 1/2CD (Perpendicular bisecting the chord)

AM = ND and MB = CN (As AB = CD)

In triangle OME and ONE, we have,

OM = MN (Equal chords are equidistant from the centre)

<OME = <ONE (90⁰)

OE is common. Thus triangle OME and ONE are congruent (RHS).

ME = EN (cpct)

So, AM + ME = ND + EN

or, AE = DE (i)

As MB = CN and ME = EN,

MB - ME = CN - EN 

= EB = CE (ii)

Hope that helps !!

Please mark my answer as brainliest.

Answer 2

Answer:

ur answer is in picture hope it helps u........

___________@divu