if two equal chords of a circle intersect within the circle prove that the line segment joining intersection to the centre makes equal angle with the chord
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Solution:
Let's suppose that we have circle with centre O. There are two equal chords AB and CD intersecting at point E.
Construction: Draw OM⊥AB and ON⊥CD. Join OE.
We need to prove that ∠OEM=∠OEN
In △OME and △ONE, we have
∠OME=∠ONE (Each equal to 90°)
OE=OE (Common)
OM=ON (Equal chords are equidistant from the centre)
Therefore, by RHS congruence rule, we have △OME≅△ONE
⇒∠OEM=∠OEN (Corresponding parts of congruent triangles are equal)
hope, this will help you.
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